Question

\(\sqrt{2-3x}=4\)

Answer 1

\(\sqrt[]{2-3x}=4\left(x\le\dfrac{2}{3}\right)\)

\(\Rightarrow2-3x=16\Rightarrow3x=-14\Rightarrow x=-\dfrac{14}{3}\)

Answer 2

\(\sqrt{2-3x}=4\)

\(\sqrt{\left(2-3x\right)^2}=4^2\) (ĐK: \(x\le\) \(\dfrac{2}{3}\))

\(2-3x=16\)

\(3x=2-16\)

\(3x=-14\)

\(x=-\dfrac{14}{3}\)