Question

 sosss

Answer 1

Bài 1:

a, \(2C_2H_5OH+2Na\rightarrow2C_2H_5ONa+H_2\)

b, \(n_{C_2H_5OH}=\dfrac{23}{46}=0,5\left(mol\right)\)

Theo PT: \(\left\{{}\begin{matrix}n_{C_2H_5ONa}=n_{C_2H_5OH}=0,5\left(mol\right)\\n_{H_2}=\dfrac{1}{2}n_{C_2H_5OH}=0,25\left(mol\right)\end{matrix}\right.\)

⇒ m_C2H5ONa = 0,5.68 = 34 (g)

V_H2 = 0,25.24,79 = 6,1975 (l)

Answer 2

Bài 2:

a, - Dẫn từng khí qua bình đựng Br₂.

+ Br₂ nhạt màu dần: C₂H₄

PT: \(C_2H_4+Br_2\rightarrow C_2H_4Br_2\)

+ Không hiện tượng: C₂H₆.

b, A: C₂H₅OH

B: CH₃CH₂CH₂OH, CH₃CH(OH)CH₃

C: CH₃CH₂CH₂CH₂OH, CH₃CH(OH)CH₂CH₃, CH₃C(CH₃)(OH)CH₃, CH₃CH(CH₃)CH₂OH

c, \(CH_2=CH_2+Br_2\rightarrow CH_2Br-CH_2Br\)

\(C_3H_8+5O_2\underrightarrow{t^o}3CO_2+4H_2O\)

\(C_2H_4+3O_2\underrightarrow{t^o}2CO_2+2H_2O\)

\(nCH_2=CH_2\underrightarrow{^{t^o,xt,p}}\left(-CH_2-CH_2-\right)_n\)

\(C_2H_5OH+3O_2\underrightarrow{t^o}2CO_2+3H_2O\)

\(C_2H_5OH+Na\rightarrow C_2H_5ONa+\dfrac{1}{2}H_2\)

\(C_6H_{12}O_6\underrightarrow{^{enzyme}}2C_2H_5OH+2CO_2\)

\(2C_xH_y+\dfrac{4x+y}{2}O_2\underrightarrow{t^o}2xCO_2+yH_2O\)

\(2C_nH_{2n}+3n_{O_2}\underrightarrow{t^o}2nCO_2+2nH_2O\)