Question

sos

Answer 1

\(B=\dfrac{2a-6\sqrt{a}+a+3\sqrt{a}-3a-3}{a-9}=\dfrac{-3\sqrt{a}-3}{a-9}\)

Answer 2

\(B=\dfrac{2\sqrt{a}}{\sqrt{a}+3}-\dfrac{\sqrt{a}}{3-\sqrt{a}}-\dfrac{3a+3}{a-9}\)

\(B=\dfrac{2a-6\sqrt{a}+a+3\sqrt{a}-3a-3}{a-9}=\dfrac{-3\sqrt{a}-3}{a-9}\)