a) Ta có:
\(12>7=>\sqrt{12}>\sqrt{7}\)
b) Ta có:
\(\sqrt{9+16}=\sqrt{25}=5\)
\(\sqrt{9}+\sqrt{16}=3+4=7\)
Vì: \(5< 7=>\sqrt{9+16}< \sqrt{9}+\sqrt{16}\)
c) Ta có:
\(24>5=>\sqrt{24}>\sqrt{5}\)
d) Ta có:
\(6\sqrt{5}=\sqrt{6^2\cdot5}=\sqrt{180}\\ 5\sqrt{6}=\sqrt{5^2\cdot6}=\sqrt{150}\)
Vì: \(180>150=>\sqrt{180}>\sqrt{150}=>6\sqrt{5}>5\sqrt{6}\)
a.√12 = 3.46410161514 ,√7 = 2.64575131106 vậy 3.46410161514 > 2.64575131106 nên √12 > √7
b.√9+16 = √25 = 5,√9 + √16 = 3 + 4 = 7 vậy 5 < 7 nên √9+16 < √9 + √16
c.√24 = 4.89897948557,√5 = 2.2360679775 vậy 4.89897948557 > 2.2360679775 nên √24 > √5
d.6√5 = 13.416407865,5√6 = 12.2474487139 vậy 13.416407865 > 12.2474487139 nên 6√5 > 5√6