Question

so sánh

100¹⁰-1/100¹⁰-3 và 100¹⁰+1/100¹⁰-1

Answer 1

\(A=\dfrac{100^{10}-3+2}{100^{10}-3}=1+\dfrac{2}{100^{10}-3}\)

\(B=\dfrac{100^{10}-1+2}{100^{10}-1}=1+\dfrac{2}{100^{10}-1}\)

100^10-3<100^10-1

=>A>B