Question

so sánh bằng cách hợp lý nhất:
a,22/11 và 11/5 b,13/8 và 7/2 c,2007/2006 và 2006/2008 

Answer 1

a: 22/11=2

11/5=2,2

Do đó: 22/11<11/5

b: 13/8<28/8=7/2

 

Answer 2

Ta có : `22/11 = 2 = 10/5`

`11/5`

Mà : `11 > 10`

`=> 22/11 <11/5`

_______________________

`13/8=1,625`

`7/2=3,5`

Mà : `1,625 < 3,5`

`=> 13/8 < 7/2`

_________________________

`2007/2006 > 1`

`2006/2008 = 1003/1004 < 1`

`=> 2007/2006 >1003/1004`

Nên : `2007/2006 > 2006/2008`

Answer 3

a) 22/11 = 2

2 = 10/5

10/5 < 11/5

=> 22/11 < 11/5

b) 13/8 < 24/8

24/8 = 3

3 = 6/2

6/2 < 7/2

=> 13/8 < 7/2

c) 2007/2006 > 2006/2006 = 1

1 = 2008/2008

2008/2008 > 2006/2008

=> 2007/2006 > 2006/2008

 

Answer 4

\(a,\dfrac{22}{11}=\dfrac{22:11}{11:11}=2\)

\(\dfrac{11}{5}=\dfrac{10+1}{5}=\dfrac{10}{5}+\dfrac{1}{5}=\dfrac{10:5}{5:5}+\dfrac{1}{5}=2+\dfrac{1}{5}>2\)

\(\rightarrow\dfrac{22}{11}< \dfrac{11}{5}\)

 

\(b,\dfrac{13}{8}\) giữ nguyên

\(\dfrac{7}{2}=\dfrac{28}{8}\)

\(\dfrac{13}{8}< \dfrac{28}{8}\)

\(\rightarrow\dfrac{13}{8}< \dfrac{7}{2}\)

 

\(c,\dfrac{2007}{2006}>1\)

\(\dfrac{2006}{2008}< 1\)

\(\rightarrow\dfrac{2007}{2006}>\dfrac{2006}{2008}\)