a)
\(7^{30}=\left(7^3\right)^{10}=343^{10}\)
\(3^{40}=\left(3^4\right)^{10}=81^{10}\)
mà \(343^{10}>81^{10}\)
=>\(7^{30}>3^{40}\)
b) 202^303 và 303^202
\(202^{303}=\left(202^3\right)^{100}=8242408^{100}\)
\(302^{202}=\left(302^2\right)^{100}=91204^{100}\)
\(8242408^{100}>91204^{100}
\)
202^303 > 303^202
c) 5^36 và 11^24
\(5^{36}=\left(5^6\right)^6=15625^6\)
\(11^{24}=\left(11^4\right)^6=14614^6\)
=> 5^36 > 11^24
d) 99^20 và 9999^10
\(99^{20}=\left(99^2\right)^{10}\)=\(9801^{10}\)
=>99^20 <9999^10
a: \(7^{30}=\left(7^3\right)^{10}=343^{10}\)
\(3^{40}=\left(3^4\right)^{10}=81^{10}\)
mà 343>81
nên \(7^{30}>3^{40}\)
b: \(202^{303}=\left(202^3\right)^{101}=8242408^{101}\)
\(303^{202}=\left(303^2\right)^{101}=91809^{101}\)
mà 8242408>91809
nên \(202^{303}>303^{202}\)
c: \(5^{36}=\left(5^3\right)^{12}=125^{12}\)
\(11^{24}=\left(11^2\right)^{12}=121^{12}\)
mà 125>121
nên \(5^{36}>11^{24}\)
d: Ta có: \(99^{20}=\left(99^2\right)^{10}=9801^{10}\)
mà 9801<9999
nên \(99^{20}< 9999^{10}\)
