Question

rút rọn biểu thức sau :

(x-3)2 - (x+2)(x-2)+7(x-4)+16

Answer 1

(x-3)2-(x+2)(x-2)+7(x-4)+16

=2x-6-x^2+4+7x-28+16

=2x+7x-6+4-28+16-x^2

=9x-14-x^2

Answer 2

\(\left(x-3\right)^2-\left(x+2\right)\left(x-2\right)+7\left(x-4\right)+16\)

\(=x^2-6x+9-x^2+4+7x-28+16\)

\(=x+1\)

Answer 3

(x-3)²-(x+2)(x-2)+7(x-4)+16

=x²-6x+9-x²+4+7x-28+16

=x+1