Question

Rút gọn

Answer 1

\(=\left(\dfrac{\left(\sqrt{x}-2\right)\left(\sqrt{x}-1\right)}{\left(x-1\right)\left(\sqrt{x}-1\right)}-\dfrac{\left(\sqrt{x}+2\right)\left(\sqrt{x}+1\right)}{\left(x-1\right)\left(\sqrt{x}-1\right)}\right)\left(\dfrac{x\left(\sqrt{x}-1\right)-\left(\sqrt{x}-1\right)}{\sqrt{x}}\right)\)

\(=\left(\dfrac{x-3\sqrt{x}+2}{\left(x-1\right)\left(\sqrt{x}-1\right)}-\dfrac{x+3\sqrt{x}+2}{\left(x-1\right)\left(\sqrt{x}-1\right)}\right)\left(\dfrac{\left(x-1\right)\left(\sqrt{x}-1\right)}{\sqrt{x}}\right)\)

\(=\left(\dfrac{-6\sqrt{x}}{\left(x-1\right)\left(\sqrt{x}-1\right)}\right)\left(\dfrac{\left(x-1\right)\left(\sqrt{x}-1\right)}{\sqrt{x}}\right)=-6\)