=\(\left(\dfrac{2\sqrt{x}}{\left(\sqrt{x}-3\right)\left(\sqrt{x}+2\right)}+\dfrac{\sqrt{x}}{\sqrt{x}+3}\right).\dfrac{\sqrt{x}-3}{\sqrt{x}}\)
=\(\dfrac{2\sqrt{x}\left(\sqrt{x}+3\right)+\sqrt{x}\left(\sqrt{x}-3\right)\left(\sqrt{x}+2\right)}{\left(x-9\right)\left(\sqrt{x}+2\right)}.\dfrac{\sqrt{x}-3}{\sqrt{x}}\)
=\(\dfrac{2x+6\sqrt{x}+\sqrt{x}\left(x-\sqrt{x}-6\right)}{\left(\sqrt{x}+3\right)\left(\sqrt{x}+2\right)}.\dfrac{1}{\sqrt{x}}\)
=\(\dfrac{2x+6\sqrt{x}+x\sqrt{x}-x-6\sqrt{x}}{\sqrt{x}\left(\sqrt{x}+3\right)\left(\sqrt{x}+2\right)}\)
=\(\dfrac{x+x\sqrt{x}}{\sqrt{x}\left(\sqrt{x}+3\right)\left(\sqrt{x}+2\right)}\)
=\(\dfrac{x+\sqrt{x}}{\left(\sqrt{x}+3\right)\left(\sqrt{x}+2\right)}\)
Giusp em với mọi người ạ. Rút gọn câu d, e, f, b giúp em với ạ, Em cảm ơn nhiều lắm.
Rút gọn giúp mình với ạ
