Question

Rút gọn B
B= \(\dfrac{x-2\sqrt{x}+4}{x-2\sqrt{x}}-\dfrac{2}{\sqrt{x}-2}\left(đkxđ:x>0;x\ne4\right)\)

Answer 1

\(B=\dfrac{x-2\sqrt{x}+4}{x-2\sqrt{x}}-\dfrac{2}{\sqrt{x}-2}\) (với \(x>0,x\ne4\))

\(B=\dfrac{x-2\sqrt{x}+4}{\sqrt{x}\left(\sqrt{x}-2\right)}-\dfrac{2}{\sqrt{x}-2}\)

\(B=\dfrac{x-2\sqrt{x}+4}{\sqrt{x}\left(\sqrt{x}-2\right)}-\dfrac{2\sqrt{x}}{\sqrt{x}\left(x-2\right)}\)

\(B=\dfrac{x-2\sqrt{x}+4-2\sqrt{x}}{\sqrt{x}\left(\sqrt{x}-2\right)}\)

\(B=\dfrac{x-4\sqrt{x}+4}{\sqrt{x}\left(\sqrt{x}-2\right)}\)

\(B=\dfrac{\left(\sqrt{x}-2\right)^2}{\sqrt{x}\left(\sqrt{x}-2\right)}\)

\(B=\dfrac{\sqrt{x}-2}{\sqrt{x}}\)