Question

Rút gọn : 

A,\(\dfrac{2ax^2-4ax+2a}{5b-5b^2}\)

B,\(\dfrac{(x+y)^2-z^2}{x+y+z}\)

 

 

 

Answer 1

\(A=\dfrac{2a\left(x^2-2x+1\right)}{5b\left(1-b\right)}=\dfrac{2a\left(x-1\right)^2}{5b\left(1-b\right)}\)

\(B=\dfrac{\left(x+y+z\right)\left(x+y-z\right)}{x+y+z}=x+y-z\)