Question

phân tích 

\(x^3+6x^2+11x+6\)

Answer 1

\(x^3+3.x^2.2+3.x.2^2+2^2-x+2=\left(x+2\right)^3-\left(x+2\right)=\left(x+2\right)\left(\left(x-2\right)^2-1\right)\)

Answer 2

x³+6x²+11x+6

= x³+3x²+3x²+9x+2x+6

=x²(x+3)+ 3x(x+3)+2(x+3)

=(x+3)(x²+3x+2)

Answer 3

À, mik quên mất : (x+3)(x²+3x+2)=(x+3)( x²+x+2x+2)=(x+3)(x+1)(x+2)
 

Answer 4

=x^3 +2x^2+4x^2+8x+3x+6

=x^2(x+2)+4x(x+2)+3(x+2)

=(x+2)(x^2+4x+3)

=(x+2)[x^2+3x+x+3]

=(x+2)[x(x+3)+(x+3)]

=(x+1)(x+2)(x+3)