Ta có :\(x^3+3x^2-4=x^3-x^2+4x^2-4.\)
\(=x^2\left(x-1\right)+4\left(x^2-1\right)\)
\(=x^2\left(x-1\right)+4\left(x-1\right)\left(x+1\right)\)
\(=\left(x-1\right)\left(x^2+4x+4\right)\)
\(=\left(x-1\right)\left(x+2\right)^2\)
Vậy \(x^3+3x^2-4=\left(x-1\right)\left(x+2\right)^2\)