Question

phân tích thành nhân tử
\(27x^3-27x^2+18x-4\)
 

Answer 1

\(27x^3-27x^2+18x-4\\=27x^3-9x^2-18x^2+6x+12x-4\\=9x^2(3x-1)-6x(3x-1)+4(3x-1)\\=(3x-1)(9x^2-6x+4)\)

Answer 2

\(27x^3-27x^2+18x-4\)

\(=27x^3-9x^2-18x^2+6x+12x-4\)

\(=9x^2\left(3x-1\right)-6x\left(3x-1\right)+4\left(3x-1\right)\)

\(=\left(9x^2-6x+4\right)\left(3x-1\right)\)