Question

Phân tích thành nhân tử
1)(2x+y)²-4y²
2)64-125x³
3)x³-2x²y+xy²-4x
4)x³-y³+x²y-xy²
 

Answer 1

1: =(2x+y-2y)(2x+y+2y)

=(2x-y)(2x+3y)

2: =(4-5x)(16+20x+25x^2)

3: =x(x^2-2xy+y^2-4)

=x[(x-y)^2-4]

=x(x-y-2)(x-y+2)

4: =(x-y)(x^2+xy+y^2)+xy(x-y)

=(x-y)(x^2+2xy+y^2)

=(x-y)(x+y)^2

Answer 2

1: =(2x+y-2y)(2x+y+2y)

=(2x-y)(2x+3y)

2: =(4-5x)(16+20x+25x^2)

3: =x(x^2-2xy+y^2-4)

=x[(x-y)^2-4]

=x(x-y-2)(x-y+2)

4: =(x-y)(x^2+xy+y^2)+xy(x-y)

=(x-y)(x^2+2xy+y^2)

=(x-y)(x+y)^2