Question

phân tích thành nhân tử: x² +2x-5

Answer 1

`x^2+2x-5`

`=(x^2+2x+1)-6`

`=(x+1)^2-\sqrt6^2`

`=(x+1+\sqrt6)(x+1-\sqrt6)`

Answer 2

\(x^2+2x-5\)

\(= x^2+2x+1-6\)

\(= (x+1)^2-6\)

\(= (x+1)^2-\left(\sqrt{6}\right)^2\)

\(= \left(x+1-\sqrt{6}\right)\left(x+1+\sqrt{6}\right)\)

Answer 3

\(x^2+2x-5\)

\(=x^2+2x+1-6\)

\(=\left(x+1\right)^2-6\)

\(=\left(x+1-\sqrt{6}\right)\left(x+1+\sqrt{6}\right)\)