Question

phân tích hạng tử:

x^3 + 4x^2 + 5x + 6

Answer 1

`x^3 +4x^2 +5x+6`

`=x^3 +3x^2 +x^2 +3x+2x+6`

`=x^2(x+3)+x(x+3)+2(x+3)`

`=(x+3)(x^2 +x+2)`

Answer 2

\(x^3+4x^2+5x+6\\ =x^3+3x^2+x^2+3x+2x+6\\ =x^2\left(x+3\right)+x\left(x+3\right)+2\left(x+3\right)\\ =\left(x+3\right)\left(x^2+x+2\right)\\ \)

Answer 3

`x^3 + 4x^2 + 5x + 6`

`=x^3+3x^2+x^2+3x+2x+6`

`=x^2.x+3x^2+x.x+3x+2x+2.3`

`=x^2(x+3)+x(x+3)+2(x+3)`

`=(x^2+x+2)(x+3)`