Question

phân tích đa thức thành nhân tử:

\(x^2\left(x-3\right)+12-4x\)

\(x^3-4x^2-12x+27\)

 

Answer 1

a)²(x-3)+12-4x

=x²(x-3)-4(x-3)

=(x²-4)(x-3)

=(x²-2²)(x-3)

=(x+2)(x-2)(x-3)

b)x³-4x²-12x+27

=x³-7x²+9x+3x²-21x+27

=x(x²-7x+9)+3(x²-7x+9)

=(x+3)(x²-7x+9)

Answer 2

a)\(x^2\left(x-3\right)+12-4x\)

\(=x^2\left(x-3\right)-4\left(x-3\right)\)

\(=\left(x^2-2^2\right)\left(x-3\right)\)

\(=\left(x+2\right)\left(x-2\right)\left(x-3\right)\)

Answer 3

\(x^2\left(x-3\right)+12-4x\)

\(=x^2\left(x-3\right)-4\left(x-3\right)\)

\(=\left(x-3\right)\left(x^2-4\right)\)

\(=\left(x-3\right)\left(x-2\right)\left(x+2\right)\)