Question

phân tích đa thức thành nhân tử:

áp dụng 7 hàng đẳng thức

a, x^6-y^6

b,10ab+0,25a^2+100b^2

c, 9x^2-xy+1/36y^2

Answer 1

a) \(x^6-y^6\)

\(=\left(x^3\right)^2-\left(y^3\right)^2\)

\(=\left(x^3-y^3\right)\left(x^3+y^3\right)\)

\(=\left(x-y\right)\left(x^2+xy+y^2\right)\left(x+y\right)\left(x^2-xy+y^2\right)\)

b) \(10ab+0,25a^2+100b^2\)

\(=\left(0,5a\right)^2+2\cdot0,5a\cdot10b+\left(10b\right)^2\)

\(=\left(0,5a+10b\right)^2\)

c) \(9x^2-xy+\frac{1}{36}y^2\)

\(=\left(3x\right)^2-2\cdot3x\cdot\frac{1}{6}y+\left(\frac{1}{6}y\right)^2\)

\(=\left(3x-\frac{1}{6}y\right)^2\)