Question

Phân tích đa thức thành nhân tử

1) 8x³+27y³-(2x+3y)

2) x³+3x²y+x+3xy²+y+y³

Answer 1

\(1,=\left(2x+3y\right)\left(4x^2-6xy+9y^2\right)-\left(2x+3y\right)\\ =\left(2x+3y\right)\left(4x^2-6xy+9y^2-1\right)\\ 2,=\left(x^3+3x^2y+3xy^2+y^3\right)+\left(x+y\right)\\ =\left(x+y\right)^3+\left(x+y\right)\\ =\left(x+y\right)\left[\left(x+y\right)^2+1\right]\)

Answer 2

`a, = (2x+3y)(4x^2 - 6xy + 9y^2) - (2x+3y)`

`= (2x+3y)(4x^2 - 6xy + 9y^2-1)`