Question

Phân tích đa thức thành nhân tử 

x^2-xy+2x-2y

ax+ay-2x-2y

ax^2-3axy+bx-3by

2a^2-5by-5a^2y+2bx

 

Answer 1

Answer 2

x²-xy+2x-2y
= (x²-xy)+(2x-2y)
= x(x-y)+2(x-y)
= (x-y)(x+2)

ax+ay-2x-2y
= (ax+ay)-(2x+2y)
= a(x+y)-2(x+y)
=(x+y)(a-2)

ax²-3axy+bx-3by
= (ax²+bx)-(3axy+3by)
= x(ax+b)-3y(ax+b)
= (ax+b)(x-3y)

2a²-5by-5a²y+2bx
= (2a²-5a²y)+(2bx-5by)
= a²(2-5y)+b(2x-5y)

Answer 3

x²-xy+2x-2y=(x²-xy)+(2x-2y)=x(x-y)+2(x-y)=(x-y)(x+2)

ax+ay-2x-2y=(ax+ay)-(2x+2y)=a(x+y)-2(x+y)=(x+y)(a-2)

ax²-3axy+bx-3by=(ax²+bx)-(3axy+3by)=x(ax+b)-3y(ax+b)=(ax+b)(x-3y)

 

Answer 4

a) Ta có: \(x^2-xy+2x-2y\)

\(=x\left(x-y\right)+2\left(x-y\right)\)

\(=\left(x-y\right)\left(x+2\right)\)

b) Ta có: \(ax+ay-2x-2y\)

\(=a\left(x+y\right)-2\left(x+y\right)\)

\(=\left(x+y\right)\left(a-2\right)\)

Answer 5

c) Ta có: \(ax^2-3axy+bx-3by\)

\(=x\left(ax+b\right)-3y\left(ax+b\right)\)

\(=\left(ax+b\right)\left(x-3y\right)\)

d) Ta có: \(2a^2-5by-5a^2y+2bx\)

\(=2\left(a^2+bx\right)-5y\left(a^2+bx\right)\)

\(=\left(a^2+bx\right)\left(2-5y\right)\)