Question

phân tích đa thức thành nhân tử x^2-4-3(x-2)

Answer 1

\(x^2-4-3\left(x-2\right)\)

\(=\left(x-2\right)\left(x+2\right)-3\left(x-2\right)\)

\(=\left(x-2\right)\left(x+2-3\right)=\left(x-2\right)\left(x-1\right)\)

Answer 2

x² - 4 - 3(x - 2)

= (x - 2)(x + 2) - 3(x - 2)

= (x - 2)(x + 2 - 3)

= (x - 2)(x - 1)

Answer 3

x^2-4-3(x-2)

= x^2  - 3x + 2

= x^2  - 2x - x + 2

= (x^2  - 2x) - (x - 2)

=x( x - 2) - ( x - 2)

= ( x - 1)( x - 2)

Answer 4

x^2-4-3(x-2) = (x-2)(x-1)

nha bạn chúc bạn học tốt nha 

Answer 5

\(x^2-4-3\left(x-2\right)\)

\(\Leftrightarrow x^2-4-3x+2\)

\(\Leftrightarrow x^2-3x+2\\ \Leftrightarrow x^2-x-2x+2\\ \Leftrightarrow\left(x^2-x\right)-\left(2x-2\right)\)

\(\Leftrightarrow x\left(x-1\right)-2\left(x-1\right)\\ \Leftrightarrow\left(x-1\right).\left(x-2\right)\)