Question

phân tích đa thức thành nhân tử theo dạng tách đa thức

a/ x²-4x+3

b/ 3x²-5x+2

thank trước nha

Answer 1

a/ \(x^2-4x+3=\left(x^2-x\right)-\left(3x-3\right)=x\left(x-1\right)-3\left(x-1\right)=\left(x-1\right)\left(x-3\right)\)

b/ \(3x^2-5x+2=\left(3x^2-3x\right)-\left(2x-2\right)=3x\left(x-1\right)-2\left(x-1\right)=\left(x-1\right)\left(3x-2\right)\)

Answer 2

\(x^2-4x+3\)

\(=x^2-3x-x-3\)

\(=x\left(x-1\right)-3\left(x-1\right)\)

\(=\left(x-3\right)\left(x-1\right)\)

\(3x^2-5x+2\)

\(=3x^2-3x-2x+2\)

\(=3x\left(x-1\right)-2\left(x-1\right)\)

\(=\left(3x-2\right)\left(x-1\right)\)

Answer 3

a/ x²-4x+3=x²-x-3x+3=x(x-1)-3(x-1)=(x-3)(x-1)

b/ 3x²-5x+2=3x²-3x-2x+2=3x(x-1)-2(x-1)=(3x-2)(x-1)