Question

Phân tích đa thức thành nhân tử : \(\left(x+2\right)^2-\left(x-2\right)^2\)

Answer 1

\(\left(x+2\right)^2-\left(x-2\right)^2\)

\(=\left(x+2-x+2\right)\left(x+2+x-2\right)\)

\(=4.2x\)

\(=8x\)

Answer 2

\(=\left[\left(x+2\right)-\left(x-2\right)\right]\cdot\left[\left(x+2\right)+\left(x-2\right)\right]\)

Answer 3

(x + 2)² - (x - 2)²

= (x + 2 - x + 2).(x + 2 + x - 2)

= 4.2x

= 8x

Answer 4

\(\left(x+2\right)^2-\left(x-2\right)^2\)

\(=\left(x+2-x+2\right)\left(x+2+x-2\right)\)

\(=8x\)

Answer 5

\(\left(x+2-x+2\right)\left(x+2+x-2\right)\)

=8x

Answer 6

=\(x^2+4x+4-x^2+4x-4=8x\)