Question

Phân tích đa thức thành nhân tử dùng phương pháp tách một hạng tử

A=x²—7xy+12y²

B=x²—3xy—4y²

Answer 1

\(A=x^2-7xy+12y^2\)

\(A=x^2-3xy-4xy+12y^2\)

\(A=x\left(x-3y\right)-4y\left(x-3y\right)\)

\(A=\left(x-4y\right)\left(x-3y\right)\)

\(B=x^2-3xy-4y^2\)

\(B=x^2+xy-4xy-4y^2\)

\(B=x\left(x+y\right)-4y\left(x+y\right)\)

\(B=\left(x-4y\right)\left(x+y\right)\)

Answer 2

\(A=x^2-7xy+12y^2\)

\(=x^2-3xy-4xy+12y^2\)

\(=x\left(x-3y\right)-4y\left(x-3y\right)\)

\(=\left(x-4y\right)\left(x-3y\right)\)

Answer 3

\(B=x^2-3xy-4y^2\)

\(=x^2+xy-4xy-4y^2\)

\(=x\left(x+y\right)-4y\left(x+y\right)\)

\(=\left(x-4y\right)\left(x+y\right)\)

Answer 4

\(A=x^2-7xy+12y^2\)

\(=x^2-3xy-4xy+12y^2\)

\(=x\left(x-3y\right)-4y\left(x-3y\right)\)

\(=\left(x-4y\right)\left(x-3y\right)\)

\(B=x^2-3xy-4y^2\)

\(=x^2+xy-4xy-4y^2\)

\(=x\left(x+y\right)-4y\left(x+y\right)\)

\(=\left(x-4y\right)\left(x+y\right)\)

~ Rất vui vì giúp đc bn ~