\(1-2y+y^2=\left(y-1\right)^2\)
\(\left(x+1\right)^2-25=\left(x-1\right)^2-5^2=\left(x-6\right)\left(x+4\right)\)
\(1-4x^2=1-\left(2x\right)^2=\left(1-2x\right)\left(1+2x\right)\)
\(8-27x^3=\left(2-3x\right)\left(4+6x+9x^2\right)\)
\(27+27x+9x^2+x^3=\left(x+3\right)^3\)
\(8x^3-12x^2y+6xy^2-y^3=\left(2x-y\right)^3\)
\(x^3+8y^3=\left(x+2y\right)\left(x^2-2xy+4y^2\right)\)
Tham khảo nhé~
Mấy cái này chỉ áp dụng HĐT thoyy nha!
\(a,1-2y+y^2=\left(1-y\right)^2\)
\(b,\left(x-1\right)^2-25=\left(x-1-5\right)\left(x-1+5\right)=\left(x-6\right)\left(x+4\right)\)
\(c,1-4x^2=\left(1-2x\right)\left(1+2x\right)\)
\(d,8-27x^3=\left(2-3x\right)\left(4+6x+9x^2\right)\)
\(e,27+27x+9x^2+x^3=\left(x+3\right)^3\)
\(f,8x^3-12x^2y+9xy^2-y^3=\left(2x-y\right)^2\)
\(g,x^3+8y^3=\left(x+2y\right)\left(x^2-2xy+y^2\right)=\left(x+2y\right)\left(x-y\right)^2\)
=.= hok tốt!!
\(a,1-2y+y^2=y^2-2y+1.\)
\(=\left(y-1\right)^2\)
\(b,\left(x+1\right)^2-25=\left(x+1\right)^2-5^2\)
\(=\left(x+1+5\right)\left(x+1-5\right)\)
\(d,8-27^3=2^3-27^3=\left(2-27\right)\left(2^2+2.27+27^2\right)\)
\(e,27+27x+9x^2+x^3=3^3+3.3^2x+3.3.x^2+x^3\)
\(=\left(3+x\right)^3\)
\(g,x^3+8y^3=x^3+\left(2x\right)^3=\left(x+2x\right)\left(x^2+2x.x+2x^2\right)\)
\(=\left(x+2x\right)\left(x^2+2x^2+4x\right)\)
phần g mk nhầm xíu nha bn,tham khảo bn cn lại nha
a) = 12-2.y.1+y2 = (1-y)2
b) = (x+1)2 - 52 = (x+1-5)(x+1+5) = (x-4)(x+6)
c) = 12-(2x)2 = (1-2x)(1+2x)
d) =23-(3x)3 = (2-3x)(4+6x+9x2)
e) = 33+3.32.x+3.3.x2+x3 = (3+x)3
f) = (2x)3 - 3.(2x)2.y + 3.2x.y2 - y3 = (2x-y)3
g) x3+(2y)3= (x+2y)(x2-2xy+4y2)
