Question

phân tích đa thức sau thành nhân tử

a) x⁴-27x

b) 27x⁵+x²

Answer 1

\(x^4-27x=x\left(x^3-27\right)=x\left(x-3\right)\left(x^2+3x+9\right)\)

\(27x^5+x^2=x^2\left(27x^3+1\right)=x^2\left[\left(3x\right)^3+1^3\right]=x^2\left(3x+1\right)\left(9x^2-3x+1\right)\)

Answer 2

a) x⁴-27x=x(x³-27)=x(x-3)(x²-3x+9)

b) 27x⁵+x²=x²(27x³+1)=x²(3x+1)(9x²-3x+1)