`3 1/3x+16 3/4=-13,25`
`10/3x+67/4=-53/4`
`10/3x=-53/4-67/4`
`10/3x=-120/4=-30`
`x=-30:10/3=-9`
\(=>\dfrac{10}{3}x+\dfrac{67}{4}=-\dfrac{53}{4}\)
\(\Leftrightarrow x=\left(-\dfrac{53}{4}-\dfrac{67}{4}\right):\dfrac{10}{3}=-\dfrac{120}{4}:\dfrac{10}{3}=-30:\dfrac{10}{3}=-9\)