\(sin\dfrac{B}{2}=\dfrac{b}{2\sqrt{ac}}\Rightarrow sin^2\dfrac{B}{2}=\dfrac{b^2}{4ac}\Rightarrow\dfrac{1-cosB}{2}=\dfrac{b^2}{4ac}\)
\(\Rightarrow1-\dfrac{a^2+c^2-b^2}{2ac}=\dfrac{b^2}{2ac}\Rightarrow2ac-a^2-c^2+b^2=b^2\)
\(\Rightarrow-\left(a-c\right)^2=0\Rightarrow a=c\)
\(\Rightarrow\Delta ABC\) cân tại B