-mNaOH(dd2)= (200*23,56%)/100%=47,12(gam)
-mdd1=(47,12*100%)/20%=235,6(gam)=> a= 235,6(gam)
=> mNaOH(dd1)=mNaOH(dd2)=47,12(gam)
-PTHH: Na + H2O -> 2NaOH(dd1)
-mNaOH=(gam) => nNaOH=47,12/40=1,178(mol)
-Theo pt: nNa=1/2nNaOH => nNa=1/2*1,178=0,589(mol)
=> mNa= 0,589*23=13,547(gam) => m=13,547 (gam)