b: \(\frac{6x-3}{x}:\frac{4x^2-1}{3x^2}\)
\(=\frac{3\left(2x-1\right)}{x}\cdot\frac{3x^2}{\left(2x-1\right)\left(2x+1\right)}\)
\(=\frac{9x^2}{x\left(2x+1\right)}=\frac{9x}{2x+1}\)
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