Question

Mk cần gấp ạ

Answer 1

\(\left(2x-3\right)^2-\left(x+3\right)^2=0\\ \Rightarrow\left(2x-3-x-3\right)\left(2x-3+x+3\right)=0\\ \Rightarrow3x\left(x-6\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=0\\x=6\end{matrix}\right.\)