Question

mình đag cần rất gấp

Answer 1

\(c,\dfrac{-2}{7}+\dfrac{4}{7}x=\dfrac{5}{7}\\ \Rightarrow\dfrac{4}{7}x=\dfrac{5}{7}+\dfrac{2}{7}\\ \Rightarrow\dfrac{4}{7}x=1\\ \Rightarrow x=1:\dfrac{4}{7}\\ \Rightarrow x=\dfrac{7}{4}\\ d,\dfrac{3}{4}:x-\dfrac{5}{4}=\dfrac{-1}{2}\\ \Rightarrow\dfrac{3}{4}:x=\dfrac{-1}{2}+\dfrac{5}{4}\\ \Rightarrow\dfrac{3}{4}:x=\dfrac{3}{4}\\ \Rightarrow x=\dfrac{3}{4}:\dfrac{3}{4}\\ \Rightarrow x=1\)