Question

Mình cần lời giải chi tiết ạ Làm nhanh mình tick cho ạ

Answer 1

\(9,\dfrac{x^2-81}{10x^2-90x}=\dfrac{\left(x-9\right)\left(x+9\right)}{10x\left(x-9\right)}=\dfrac{x+9}{10x}\Rightarrow M=10x\\ 10,\dfrac{2x^2+3x}{4x^2-9}=\dfrac{x\left(2x+3\right)}{\left(2x-3\right)\left(2x+3\right)}=\dfrac{x}{2x-3}\Rightarrow A=x\)

 

Answer 2

\(9,M=\dfrac{\left(x+9\right)\left(10x^2-90x\right)}{x^2-81}=\dfrac{10x\left(x+9\right)\left(x-9\right)}{\left(x-9\right)\left(x+9\right)}=10x\\ 10,A=\dfrac{\left(2x-3\right)\left(2x^2+3x\right)}{4x^2-9}=\dfrac{x\left(2x+3\right)\left(2x-3\right)}{\left(2x-3\right)\left(2x+3\right)}=x\)