Câu 3 :
\(n_{SO_3}=\dfrac{8}{80}=0.1\left(mol\right)\)
\(SO_3+H_2O\rightarrow H_2SO_4\)
\(0.1....................0.1\)
b) Cho quỳ tím vào => quỳ tím hóa đỏ
\(m_{H_2SO_4}=0.1\cdot98=9.8\left(g\right)\)
\(C_{M_{H_2SO_4}}=\dfrac{0.1}{0.25}=0.4\left(M\right)\)
Câu 2 :
\(n_{Fe}=\dfrac{11.2}{56}=0.2\left(mol\right)\)
\(Fe_2O_3+3H_2\underrightarrow{^{t^0}}2Fe+3H_2O\)
\(0.1.........0.3.........0.2\)
\(m_{Fe_2O_3}=0.1\cdot160=16\left(g\right)\)
\(V_{H_2}=0.3\cdot22.4=6.72\left(l\right)\)
Câu 5 :
\(Zn+2HCl\rightarrow ZnCl_2+H_2\)
\(CuO+H_2\underrightarrow{^{t^0}}Cu+H_2O\)
\(FeO+H_2\underrightarrow{^{t^0}}Fe+H_2O\)
\(2Al+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2\)
