Question

 

Mg giải giúp mình ạ

Answer 1

a: \(\dfrac{13}{25}-\dfrac{31}{41}+\dfrac{12}{25}-\dfrac{10}{41}-0,5\)

\(=\left(\dfrac{13}{25}+\dfrac{12}{25}\right)-\left(\dfrac{31}{41}+\dfrac{10}{41}\right)-\dfrac{1}{2}\)

\(=1-1-\dfrac{1}{2}=-\dfrac{1}{2}\)

b: \(\left(-2\right)^3-\left(-\dfrac{1}{2}\right)^2:\dfrac{-1}{16}-2023^0\)

\(=-8-\dfrac{1}{4}\cdot\dfrac{-16}{1}-1\)

=-8+4-1

=-4-1

=-5

c: \(\left(-\dfrac{1}{3}\right)^2+\dfrac{4}{3}:2-0,6\)

\(=\dfrac{1}{9}+\dfrac{4}{3}\cdot\dfrac{1}{2}-\dfrac{3}{5}\)

\(=\dfrac{1}{9}+\dfrac{2}{3}-\dfrac{3}{5}\)

\(=\dfrac{10}{90}+\dfrac{60}{90}-\dfrac{54}{90}=\dfrac{16}{90}=\dfrac{8}{45}\)

d: \(\dfrac{2}{9}\cdot\dfrac{7}{5}+\dfrac{2}{9}\cdot\dfrac{-11}{5}+\dfrac{4}{5}\cdot\dfrac{2}{9}\)

\(=\dfrac{2}{9}\left(\dfrac{7}{5}-\dfrac{11}{5}+\dfrac{4}{5}\right)\)

\(=\dfrac{2}{9}\cdot0=0\)