\(\left|x-2016\right|=x-2012\)
\(\Leftrightarrow x-2016=2012-x\left(x< 2016\right)\)
\(\Leftrightarrow2x=4028\)
hay x=2014(nhận)
lx-2016 l=x-2012
\(\left[{}\begin{matrix}x-2016=x-2012\\x-2016=-x+2012\end{matrix}\right.\)
\(\left[{}\begin{matrix}0x=2016-2012\left(bỏ\right)\\2x=2012+2016\end{matrix}\right.\)
\(2x=4028=>x=2014\)