`(x-2/3)^3=1/27`
`(x-2/3)^3=(1/3)^3`
`x-2/3=1/3`
`x=1/3+2/3=3/3=1`
`(x-2/3)^3 = 1/27`
`=> (x-2/3)^3 = (1/3)^3`
`=> x - 2/3 = 1/3`
`=> x = 1/3 + 2/3`
`=> x = 1`
\(\left(x-\dfrac{2}{3}\right)^3=\dfrac{1}{27}\)
\(\left(x-\dfrac{2}{3}\right)^3=\left(\dfrac{1}{3}\right)^3\)
\(\Rightarrow x-\dfrac{2}{3}=\dfrac{1}{3}\)
\(x=\dfrac{1}{3}+\dfrac{2}{3}\)
\(x=1\)
Vậy \(x=1\)
\(\left(x-\dfrac{2}{3}\right)^3=\dfrac{1}{27}\)
\(\left(x-\dfrac{2}{3}\right)^3=\left(\dfrac{1}{3}\right)^3\)
\(\Rightarrow x-\dfrac{2}{3}=\dfrac{1}{3}\)
\(x=\dfrac{1}{3}+\dfrac{2}{3}\)
\(x=1\)