mn giúp vs ạ , e đang cần gấp . Ai trả lời đúng và nhanh đầu tiên e hứa sẽ k ạ
\(\left(x-1\right)^3-x\left(x-1\right)^2=5x\left(2x-x\right)-11\left(x+2\right)\)
\(\Leftrightarrow x^3-3x^2+3x-1-x^3-2x^2-x=10x-5x^2-11x-2\)
\(\Leftrightarrow2x-1=-x-22\)
\(\Leftrightarrow3x=-21\)
\(\Leftrightarrow x=7\)
văn đạt ơi , hình như sai r:(((
Tìm \(x\):
\(8\)) \(1-\left(x-6\right)=4\left(2-2x\right)\)
\(9\))\(\left(3x-2\right)\left(x+5\right)=0\)
\(10\))\(\left(x+3\right)\left(x^2+2\right)=0\)
\(11\))\(\left(5x-1\right)\left(x^2-9\right)=0\)
\(12\))\(x\left(x-3\right)+3\left(x-3\right)=0\)
\(13\))\(x\left(x-5\right)-4x+20=0\)
\(14\))\(x^2+4x-5=0\)
BÀI 6 tìm x
1,\(2x\left(x-5\right)-\left(3x+2x^2\right)=0\) 2,\(x\left(5-2x\right)+2x\left(x-1\right)=13\)
3,\(2x^3\left(2x-3\right)-x^2\left(4x^2-6x+2\right)=0\) 4,\(5x\left(x-1\right)-\left(x+2\right)\left(5x-7\right)=6\)
5,\(6x^2-\left(2x-3\right)\left(3x+2\right)=1\) 6,\(2x\left(1-x\right)+5=9-2x^2\)
BT3: Tìm x
\(a,\left(x+2\right)^2-9=0\)
\(b,x^2-2x+1=25\)
\(c,\left(5x+1\right)^2-\left(5x-3\right)\left(5x+3\right)=30\)
\(d,\left(x-1\right)\left(x^2+x+1\right)+x\left(x+2\right)\left(2-x\right)=5\)
d) \(^{ }4x\left(2x+3\right)-8x\left(x+4\right)\)
e) \(^{ }2x\left(5x+2\right)+\left(2x-3\right)\left(3x-1\right)\)
f) \(^{ }x\left(x+2\right)^2-\left(x+1\right)^3+3\left(x-1\right)\left(x+1\right)\)
BT9: Tìm x biết
\(9,\left(2x-5\right)^2-\left(x+1\right)^2=0\)
\(10,\left(x+3\right)^2-x^2=45\)
\(11,\left(5x-4\right)^2-49x^2=0\)
\(12,16\left(x-1\right)^2-25=0\)
Giai cac bpt sau
a,\(\left(x+1\right)\left(2x-2\right)-3>-5x-\left(2x+1\right)\left(3-x\right)\)
b,\(\left(x-3^{ }\right)^2+4\left(2-x\right)>\left(x+7\right)\)
Giải các phương trình
a. \(\frac{1-x}{x+1}+3=\frac{2x+3}{x+1}\)
b. \(\frac{\left(x+2\right)^2}{2x-3}-1=\frac{x^2+10}{2x-3}\)
c. \(\left(2-3x\right)\left(x+11\right)=\left(3x-2\right)\left(2-5x\right)\)
d.\(\left(2x^2+1\right)\left(4x-3\right)=\left(2x^2+1\right)\left(x-12\right)\)
1\()\)\((\)x-1\()\)\(\left(5x+3\right)\)\(=\)\(\left(3x-8\right)\)\(\left(x-1\right)\)
2/\(\left(2x-1\right)^2\)\(+\)\(\left(2-x\right)\)\(\left(2x-1\right)\)\(=\)0
\(\left(x-1\right)^3-x\left(x-1\right)^2=5x\left(2-x\right)-11\left(x+2\right)\)
MN GIÚP MK VS Ạ
