\(\left(\sqrt{14}-3\sqrt{2}\right)^3+6\sqrt{28}\)
\(=\left(\sqrt{14}\right)^2-2\cdot3\sqrt{2}\cdot\sqrt{14}+\left(3\sqrt{2}\right)^2+6\cdot2\sqrt{7}\)
\(=14-6\sqrt{28}+9\cdot2+12\sqrt{7}\)
\(=14-6\cdot2\sqrt{7}+18+12\sqrt{7}\)
\(=\left(14+18\right)+\left(12\sqrt{7}-12\sqrt{7}\right)\)
\(=32\)