(√10 - √2)(3 + √5)√(3 - √5)
= (√10 - √2).√[(3 + √5)².(3 - √5)]
= √2(√5 - 1).√[4.(3 + √5)]
= 2√2.√[(√5 - 1)².(3 + √5)]
= 2√2.√[(5 - 2√5 + 1).(3 + √5)]
= 2√2.√(18 + 6√5 - 6√5 - 10)
= 2√2.√8
= 2√2.2√2
= 8
Gấp lắm . Giúp mình cảm ơn ạ
Bài 1
\(2\sqrt{\left(1+\sqrt{3}\right)^{ }3}-\sqrt{\left(2\sqrt{3}-3\right)^2}\)
\(\left(1+\sqrt{3}-\sqrt{5}\right).\left(1+\sqrt{3}+\sqrt{5}\right)\)
\(\left(\sqrt[]{\dfrac{8}{3}}-\sqrt{5}\right)x\sqrt{6}\)
\(\left(5+4\sqrt{2}\right).\left(3+2\sqrt{1}+\sqrt{2}\right).\left(3-2\sqrt{1}+2\right)\)
\(\sqrt{3+2\sqrt{2}}-\sqrt{3-2\sqrt{2}}\)
\(1.\sqrt{\left(2+\sqrt{7}\right)^2-\sqrt{\left(2-\sqrt{7}\right)^2}}\)
\(2.\sqrt{\left(3\sqrt{5}-5\sqrt{2}\right)^2}-\sqrt{\left(5\sqrt{2}+3\sqrt{5}\right)^2}+10\sqrt{5}\)
\(3.\sqrt{10+2\sqrt{21}}-\sqrt{10-2\sqrt{21}}\)
\(4.\sqrt{6+2\sqrt{5-\sqrt{13+4\sqrt{3}}}}\)
Nếu được thì các bạn giải thích giúp mình với ạ :3, mình cảm ơn :3
a) \(\sqrt{3+\sqrt{5}}\left(\sqrt{10}+\sqrt{2}\right)\left(3-\sqrt{5}\right)\)
b) \(2\sqrt{4+\sqrt{6-2\sqrt{5}}}\left(\sqrt{10}-\sqrt{2}\right)\)
mình đang cần gấp giải giúp mình nha
giúp tui với
\(\left(\sqrt{10}+\sqrt{2}\right)\left(6-2\sqrt{5}\right)^2\sqrt{3+\sqrt{5}}\)
\(\dfrac{4-a^2}{48}\sqrt{\dfrac{36}{a^2-4a+4}}\left(a>2\right)\)
Thực hiện phép tính
a) \(\left(3-\sqrt{3}\right)\left(-2\sqrt{3}\right)+\left(3\sqrt{3}+1\right)^2\)
b) \(\left(3\sqrt{5}-2\sqrt{3}\right).\sqrt{5}+\sqrt{60}\)
c) \(\left(\sqrt{28}-2\sqrt{3}+\sqrt{7}\right).\sqrt{7}+\sqrt{84}\)
- Bạn nào giúp mình với, mình cảm ơn nhìu ...!
rút gọn
a) \(\left(-7\sqrt{7}\right)\left(-2\sqrt{8}\right)\)
b) \(-\sqrt{33}.3\sqrt{3}\)
c) \(\left(3\sqrt{5}\right).\left(-10\sqrt{3}\right)\)
d) \(\dfrac{1}{2}\sqrt{5}.\left(-6\sqrt{2}\right)\)
e) \(\dfrac{2}{3}\sqrt{7}.\left(-\dfrac{9}{16}\sqrt{3}\right)\)
f) \(15\sqrt{6}:5\sqrt{3}\)
g) \(-25\sqrt{12}:\left(-5\sqrt{6}\right)\)
h) \(36\sqrt{8}:12\sqrt{2}\)
i) \(4\sqrt{27}:\left(-2\sqrt{3}\right)\)
Giải giúp mình nhé
\(\left(1+\sqrt{3}-\sqrt{2}\right).\left(1+\sqrt{3}+\sqrt{2}\right)\)
\(\left(\sqrt{3-\sqrt{5}}+\sqrt{3+\sqrt{5}}\right)^2\)
\(x^3=\left(\sqrt[3]{5+2\sqrt{6}}+\sqrt[3]{5-2\sqrt{6}}\right)^3=\sqrt[3]{5+2\sqrt{6}}^3\)
\(+3\sqrt[3]{\left(5+2\sqrt{6}\right)^2}.\sqrt[3]{5-2\sqrt{6}}+3\sqrt[3]{5+2\sqrt{6}}.\sqrt[3]{\left(5-2\sqrt{6}\right)^2}+\sqrt[3]{5-2\sqrt{6}}^3\)
\(=5+2\sqrt{6}+3\sqrt[3]{\left(5+2\sqrt{6}\right)\left(5-2\sqrt{6}\right)}.\sqrt[3]{5+2\sqrt{6}}\)
\(+3\sqrt[3]{\left(5+2\sqrt{6}\right)\left(5-2\sqrt{6}\right)}.\sqrt[3]{5-2\sqrt{6}}+5-2\sqrt{6}\)
\(=5+5+3\sqrt[3]{\left(25-4.6\right)}.\sqrt[3]{5+2\sqrt{6}}+3\sqrt[3]{\left(25-4.6\right)}.\sqrt[3]{5-2\sqrt{6}}\)
\(=10+ 3\sqrt[3]{5+2\sqrt{6}}+3\sqrt[3]{5-2\sqrt{6}}\)
p/s : có bạn hỏi nên mình đăng , các bạn đừng report nhé
1)\(\sqrt{x+3}\) > 2
2) \(\dfrac{1+\sqrt{x}}{\sqrt{x}-2}\)<1
3) \(\left(\sqrt{x}-1\right)\).\(\left(\sqrt{x}-3\right)\)-5=\(\sqrt{x}\) \(\left(\sqrt{x}+2\right)-5\)
tìm x mn giúp mình nha plsss
