\(=\dfrac{8+5}{10}\cdot\dfrac{39-120}{195}=\dfrac{13}{10}\cdot\dfrac{-81}{195}=\dfrac{1}{15}\cdot\dfrac{-81}{10}=\dfrac{-27}{5\cdot10}=-\dfrac{27}{50}\)
`(4/5+1/2).(3/15-8/13)`
`=(8/10+5/10).(39/195-120/195)`
`=13/10 . -81/195`
`=-27/50`
\(\left(\dfrac{4}{5}+\dfrac{1}{2}\right)\cdot\left(\dfrac{3}{15}-\dfrac{8}{13}\right)\)
\(=\dfrac{13}{10}\cdot\left(-\dfrac{27}{65}\right)\)
\(=-\dfrac{27}{50}\)
= ( 8/10 + 5/10 ) . (39/195 - 120/195)
= 13/10 . -81/195
= - 27/50
