Question

\(\left(\dfrac{2x-1}{3}\right)^2=\dfrac{1}{4}\)

Answer 1

\(\Leftrightarrow\left[{}\begin{matrix}\dfrac{2x-1}{3}=\dfrac{1}{2}\\\dfrac{2x-1}{3}=\dfrac{-1}{2}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}4x-2=3\\4x-2=-3\end{matrix}\right.\Leftrightarrow x\in\left\{\dfrac{5}{4};-\dfrac{1}{4}\right\}\)