Question

\(\left(\dfrac{1}{3}x+\dfrac{4}{3}\right)\left(-\dfrac{1}{5}x+\dfrac{3}{5}\right)\)=0

Answer 1

\(\left(\dfrac{1}{3}x+\dfrac{4}{3}\right)\left(-\dfrac{1}{5}x+\dfrac{3}{5}\right)=0\)

⇔ \(\dfrac{1}{3}x+\dfrac{4}{3}=0\) hoặc \(-\dfrac{1}{5}x+\dfrac{3}{5}=0\)

⇔     \(x=-4\)    hoặc    \(x=3\)

Vậy x = - 4 hoặ x = 3

Answer 2

\(\left(\dfrac{1}{3}x+\dfrac{4}{3}\right)\left(-\dfrac{1}{5}x+\dfrac{3}{5}\right)=0\\ \Rightarrow\left[{}\begin{matrix}\dfrac{1}{3}x+\dfrac{4}{3}=0\\-\dfrac{1}{5}x+\dfrac{3}{5}=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=-4\\x=3\end{matrix}\right.\)