Question

\(\left(\dfrac{1}{2}\right)^5\) - 1,5^{2 +} \(\dfrac{31}{32}\) + 102,25

Answer 1

Cứu vs

Answer 2

\(\left(\dfrac{1}{2}\right)^5\)-\(1,5^2\)+\(\dfrac{31}{32}\)+102,25

= \(\dfrac{1}{32}\)+\(\dfrac{31}{32}\)-\(\dfrac{9}{4}\)+\(\dfrac{409}{4}\)

= \(\left(\dfrac{1}{32}+\dfrac{31}{32}\right)\)+\(\left(\dfrac{409}{4}-\dfrac{9}{4}\right)\)

= 1+100

=101

Answer 3

\(\left(\dfrac{1}{2^{ }}\right)^5\) - 1,5² + \(\dfrac{31}{32}\) + 102,25

= \(\dfrac{1}{32}\) - 2,25 + \(\dfrac{31}{32}\) + 102,25

= (\(\dfrac{1}{32}\) + \(\dfrac{31}{32}\)) + (102,25 - 2,25)

= 1 + 100

= 101

Answer 4

\(\left(\dfrac{1}{2}\right)^5-1,5^2+\dfrac{31}{32}+102,25\)

\(=\dfrac{1}{32}-2.25+\dfrac{31}{32}+102,25\)

\(=\left(\dfrac{1}{32}+\dfrac{31}{32}\right)-2,25+102,25\)

\(=1-2,25+102,25\)

\(=\left(-1,25\right)+102,25\)

\(=101\)