\(\left(\dfrac{1}{2}\right)^5-1,5^2+\dfrac{31}{32}+102,25\)
\(=\dfrac{1}{32}+\dfrac{31}{32}-2,25+102,25\)
=1+100
=101
`(1/2)^5 - 1,5^2 + 31/32 + 102,25`
` = 1/32 - 2,25 +31/32 + 102,25`
`= (1/32 + 31/32) - (2,25 - 102,25)`
`= 1 - - 100`
`= 1 + 100`
`= 101`