Các câu hỏi tương tự
bài 2: 1, \(\left(\dfrac{5}{6}\right)^{10}.\left(\dfrac{3}{10}\right)^{10}\)2,\(\left(\dfrac{4}{7}\right)^{19}:\left(\dfrac{-12}{35}\right)^{19}\) 3,\(\left(\dfrac{-3}{7}\right)^7:\left(\dfrac{-3}{5}\right)\)
Tính:
B=\(\left(1-\dfrac{1}{3}\right)\left(1-\dfrac{1}{6}\right)\left(1-\dfrac{1}{10}\right)\left(1-\dfrac{1}{15}\right)...\left(1-\dfrac{1}{2450}\right)\)
Tính B = \(\left(1-\dfrac{1}{3}\right)\left(1-\dfrac{1}{6}\right)\left(1-\dfrac{1}{10}\right)\left(1-\dfrac{1}{15}\right)...\left(1-\dfrac{1}{2450}\right)\)
dfrac{8^{14}}{4^4.64^5}
dfrac{9^{10}.27^7}{81^7.3^{15}}
left(dfrac{3}{10}right)^4.left(0,3right)^5.left(dfrac{10}{3}right)^{10}
dfrac{left(4^3right)^2.9^4}{6^7.8^2}
dfrac{4^8.9^4}{6^6.8^3}
3^6.left(dfrac{1}{3}right)^6.81^2.dfrac{1}{27^2} TÍNH
Đọc tiếp
\(\dfrac{8^{14}}{4^4.64^5}\)
\(\dfrac{9^{10}.27^7}{81^7.3^{15}}\)
\(\left(\dfrac{3}{10}\right)^4.\left(0,3\right)^5.\left(\dfrac{10}{3}\right)^{10}\)
\(\dfrac{\left(4^3\right)^2.9^4}{6^7.8^2}\)
\(\dfrac{4^8.9^4}{6^6.8^3}\)
\(3^6.\left(\dfrac{1}{3}\right)^6.81^2.\dfrac{1}{27^2}\) TÍNH
28 tháng 9 2023 lúc 18:44
\(d,\dfrac{\left(13\dfrac{1}{4}-2\dfrac{5}{27}-10\dfrac{5}{6}\right).230\dfrac{1}{25}+46\dfrac{3}{4}}{\left(1\dfrac{3}{7}+\dfrac{10}{3}\right):\left(12\dfrac{1}{3}-14\dfrac{2}{7}\right)}\)
\(\dfrac{\left(\dfrac{1}{2}\right)^{10}.5-\left(\dfrac{1}{4}\right)^5.3}{\dfrac{1}{1024}.\dfrac{1}{3}-\left(\dfrac{1}{2}\right)^{11}}\)
\(A=\left(\dfrac{1}{5}+\dfrac{2013}{2014}+\dfrac{2015}{2016}+1\right)\left(\dfrac{2013}{2014}+\dfrac{2015}{2016}+\dfrac{1}{10}\right)-\left(\dfrac{1}{5}+\dfrac{2013}{2014}+\dfrac{2015}{2016}\right)\left(\dfrac{2013}{2014}+\dfrac{2015}{2016}+\dfrac{1}{10}+1\right)\)
cho A = \(\left(\dfrac{1}{2}-1\right)\left(\dfrac{1}{2}-1\right).....\left(\dfrac{1}{10}-1\right)\). so sánh a với \(-\dfrac{1}{9}\)
tìm x,y biết:
a) \(x^2+\left(y-\dfrac{1}{10}\right)^4=0\)
b) \(\left(\dfrac{1}{2}.x-5\right)^{20}+\left(y^2-\dfrac{1}{4}\right)^{10}\le0\)
16 tháng 7 2023 lúc 16:39
Tìm x biết:
\(\dfrac{1}{3}+\dfrac{1}{6}+\dfrac{1}{10}+\dfrac{1}{15}+...+\dfrac{1}{x\left(2x+1\right)}=\dfrac{1}{10},\left(x\inℕ^∗\right)\)
Giải chi tiết giúp mik nha.