Question

\(\left|\bigg(x+\dfrac{1}{2}\bigg)\bigg|2x-\dfrac{3}{4}\bigg|\right| =2x-\dfrac{3}{4}\)

Answer 1

`|(x+1/2)|2x-3/4||=2x-3/4`               `ĐK: x >= 3/8`

`=>[((x+1/2)(2x-3/4)=2x-3/4),((x+1/2)(2x-3/4)=3/4-2x):}`

`@TH1:x=3/8`

   `=>[((3/8+1/2).0=0(LĐ)),((3/8+1/2).0=0(LĐ)):}`

  `=>x=3/8` t/m

`@TH2:x > 3/8=>[(x+1/2=1),(x+1/2=-1):}=>[(x=1/2(t//m)),(x=-3/2(ko t//m)):}`

Vậy `x in {3/8;1/2}`