ĐKXĐ: x<>3 và y<>-2
\(\left\{{}\begin{matrix}\dfrac{12}{x-3}-\dfrac{5}{y+2}=63\\\dfrac{8}{x-3}+\dfrac{15}{y+2}=-13\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}\dfrac{36}{x-3}-\dfrac{15}{y+2}=189\\\dfrac{8}{x-2}+\dfrac{15}{y+2}=-13\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}\dfrac{44}{x-3}=176\\\dfrac{8}{x-3}+\dfrac{15}{y+2}=-13\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}x-3=\dfrac{1}{4}\\\dfrac{15}{y+2}=-13-8:\dfrac{1}{4}=-13-32=-45\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}x-3=\dfrac{1}{4}\\y+2=-\dfrac{1}{3}\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}x=\dfrac{13}{4}\\y=-\dfrac{7}{3}\end{matrix}\right.\left(nhận\right)\)
